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Sprendimas.

3

/ (2-x)

=

3

/ (2-x)

= $\frac{3}{2-x}$ =

3* (2+saknis(

2))

/ (2-saknis(

2))/ (2+saknis(

2))

= $\frac{3\cdot (2+\sqrt {2})}{(2-\sqrt {2})\cdot (2+\sqrt {2})}$ =

$\frac{3}{2-x}$ =

$\frac{3}{2-\sqrt {2}}$ =

$\frac{3\cdot (2+\sqrt {2})}{(2-\sqrt {2})\cdot (2+\sqrt {2})}$ =

$\frac{3\cdot (2+\sqrt {2})}{2^{2}-\sqrt {2}^{2}}$ =

$\frac{3\cdot (2+\sqrt {2})}{4-2}$ =

$\frac{3\cdot (2+\sqrt {2})}{2}$ =

$\frac{6+3\cdot \sqrt {2}}{2}$

Atsakymas: D

4 uždavinys6 uždavinys