10 uždavinys
Sprendimas.
| (sin(a)-cos(a)) |
| / cos(a) |
2
|
| (sin(a)-cos(a)) |
| / cos(a) |
$${\normalsize \frac{sin(a)-cos(a)}{cos(a)}}$$ = $${\normalsize \frac{sin(a)}{cos(a)}-\frac{cos(a)}{cos(a)}}$$
| sin(a) |
| / cos(a) |
| cos(a) |
| / cos(a) |
$${\normalsize \frac{cos(a)}{cos(a)}}$$ = $${\normalsize 1}$$
| sin(a) |
| / cos(a) |
$${\normalsize \frac{sin(a)}{cos(a)}}$$ = $${\normalsize \frac{sin(a)}{cos(a)}}$$
tg(a)-1 = 2$$tg(a)-1$$ = $$2$$
tg(a) = 2+1$$tg(a)$$ = $$2+1$$
$${\normalsize 2+1}$$ = $${\normalsize 3}$$
tg(a) = 3$$tg(a)$$ = $$3$$
$$\frac{sin(a)-cos(a)}{cos(a)}$$ = $$2$$
$$\frac{sin(a)}{cos(a)}-\frac{cos(a)}{cos(a)}$$ = $$2$$
$$tg(a)-1$$ = $$2$$
$$tg(a)$$ = $$3$$
Atsakymas: D