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Ištraukite šaknį: $$\sqrt {12\cdot 27}$$
Sprendimas.
saknis(
12* 27) =
12* 27) = |
|
saknis( 12* 27) = $$\sqrt {12\cdot 27}$$ =
12* 27) = $$\sqrt {12\cdot 27}$$ = saknis( 3* 4* 27) = $$\sqrt {3\cdot 4\cdot 27}$$ =
3* 4* 27) = $$\sqrt {3\cdot 4\cdot 27}$$ = saknis( 3* 4* 3* 9) = $$\sqrt {3\cdot 4\cdot 3\cdot 9}$$ =
3* 4* 3* 9) = $$\sqrt {3\cdot 4\cdot 3\cdot 9}$$ = saknis( 4* 3* 3* 9) = $$\sqrt {4\cdot 3\cdot 3\cdot 9}$$ =
4* 3* 3* 9) = $$\sqrt {4\cdot 3\cdot 3\cdot 9}$$ = $${\normalsize 3\cdot 3}$$ = $${\normalsize 9}$$
saknis( 4* 9* 9) = $$\sqrt {4\cdot 9\cdot 9}$$ =
4* 9* 9) = $$\sqrt {4\cdot 9\cdot 9}$$ = saknis( 2* 2* 9* 9) = $$\sqrt {2\cdot 2\cdot 9\cdot 9}$$ =
2* 2* 9* 9) = $$\sqrt {2\cdot 2\cdot 9\cdot 9}$$ = $${\normalsize 2\cdot 2}$$ = $${\normalsize 2^{2}}$$
saknis( 2^2* 9* 9) = $$\sqrt {2^{2}\cdot 9\cdot 9}$$ =
2^2* 9* 9) = $$\sqrt {2^{2}\cdot 9\cdot 9}$$ = $${\normalsize 9\cdot 9}$$ = $${\normalsize 9^{2}}$$
saknis( 2^2* 9^2) = $$\sqrt {2^{2}\cdot 9^{2}}$$ =
2^2* 9^2) = $$\sqrt {2^{2}\cdot 9^{2}}$$ = $${\normalsize \sqrt {2^{2}\cdot 9^{2}}}$$ = $${\normalsize 18}$$
2* 9 = $$2\cdot 9$$ =
$${\normalsize 2\cdot 9}$$ = $${\normalsize 18}$$
18$$18$$
$$\sqrt {12\cdot 27}$$ = $$$$
$$\sqrt {4\cdot 3\cdot 3\cdot 9}$$ = $$$$
$$\sqrt {2^{2}\cdot 9^{2}}$$ = $$$$
$$2\cdot 9$$ = $$$$
$$18$$ $$$$
Atsakymas: 18