Sprendimas: jxu3jU - 1
S_n =
S_0* (1+
)
S_0* (1+
| p |
| / 100 |
|
S_n = S_0* (1+
)$$S_{n}$$ = $$S_0\cdot (1+\frac{p}{100})$$
| p |
| / 100 |
S_0* (1+
) = S_n$$S_0\cdot (1+\frac{p}{100})$$ = $$S_{n}$$
| p |
| / 100 |
(1+
) =
$$(1+\frac{p}{100})$$ = $$\frac{S_{n}}{S_0}$$
| p |
| / 100 |
| S_n |
| / S_0 |
1+
=
$$1+\frac{p}{100}$$ = $$\frac{S_{n}}{S_0}$$
| p |
| / 100 |
| S_n |
| / S_0 |
| p |
| / 100 |
| S_n |
| / S_0 |
p = 100* (
-1)$$p$$ = $$100\cdot (\frac{S_{n}}{S_0}-1)$$
| S_n |
| / S_0 |
p =
-100$$p$$ = $$\frac{100\cdot S_{n}}{S_0}-100$$
| 100* S_n |
| / S_0 |