5 uždavinys

Sprendimas:

 $$\frac{2}{3+\sqrt {3}} = $$   $$\frac{2\cdot (3-\sqrt {3})}{(3+\sqrt {3})\cdot (3-\sqrt {3})} = $$   $$\frac{2\cdot (3-\sqrt {3})}{3^{2}-\sqrt {3}^{2}} = $$    $$\frac{2\cdot (3-\sqrt {3})}{9-3} = $$   $$\frac{2\cdot (3-\sqrt {3})}{6} = $$    $$\frac{3-\sqrt {3}}{3}$$

Atsakymas: B  $$\frac{3-\sqrt {3}}{3}$$