19 uždavinys

Sprendimas.

2^^{(5-x^2)} ≤
16

2^^{(5-x^2)} ≤ 16 $2^{(5-x^2)}$ ≤ $16$

log(₂, 2^^{(5-x^2)}) ≤ log(₂,16) $log_{2}(2^{(5-x^2)})$ ≤ $log_{2}(16)$

(5- x^²) ≤ 4 $(5-x^{2})$ ≤ $4$

5 ≤ 4+ x^² $5$ ≤ $4+x^{2}$

5-4 ≤ x^² $5-4$ ≤ $x^{2}$

x^² ≥ 1 $x^{2}$ ≥ $1$

$2^{(5-x^2)}$ ≤ $16$

$log_{2}(2^{(5-x^2)})$ ≤ $log_{2}(16)$

$log_{2}(2^{(5-x^2)})$ ≤ $4$

$5-x^{2}$ ≤ $4$

$5-4$ ≤ $x^{2}$

$1$ ≤ $x^{2}$

$x^{2}$ ≥ $1$

x priklauso [-∞; -1] U [ 1; +∞]

Atsakymas: x priklauso [-∞; -1] U [ 1; +∞]

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